Answer
$\frac 1 2 x^2+x+ln|x-1|+C$
Work Step by Step
$\int \frac {x^2}{x-1}dx$
$\int(x+1)dx+\int \frac 1 {x-1}dx$
$\frac 1 2 x^2+x+ln|x-1|+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 23
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