Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.3 - Simplifying Complex Fractions - Exercise Set - Page 361: 60

Answer

$\dfrac{9E}{I}$

Work Step by Step

The given expression, $ \dfrac{E}{\dfrac{I}{9}} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{\dfrac{E}{1}}{\dfrac{I}{9}} .\end{array} Using $\dfrac{\frac{a}{b}}{\frac{c}{d}}=\dfrac{a}{b}\div\dfrac{c}{d}=\dfrac{a}{b}\cdot\dfrac{d}{c},$ the expression above is equivalent to \begin{array}{l}\require{cancel} \dfrac{E}{1}\cdot\dfrac{9}{I} \\\\= \dfrac{9E}{I} .\end{array}
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