Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.3 - Simplifying Complex Fractions - Exercise Set - Page 361: 56

Answer

$y=\{-1,0\}$

Work Step by Step

Since for any non-negative number $c$, $|x|=c$ implies $x=c \text{ OR } x=-c$, then the values that satisfy the given equation, $ |2y+1|=1 ,$ are \begin{array}{l}\require{cancel} 2y+1=1 \\\\ 2y=1-1 \\\\ 2y=0 \\\\ y=\dfrac{0}{2} \\\\ y=0 \\\\\text{ OR }\\ 2y+1=-1 \\\\ 2y=-1-1 \\\\ 2y=-2 \\\\ y=-\dfrac{2}{2} \\\\ y=-1 .\end{array} Hence, $ y=\{-1,0\} .$
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