Answer
$-\dfrac{2x^3}{y(x-y)}$
Work Step by Step
The given expression, $
\dfrac{\dfrac{-2x}{x-y}}{\dfrac{y}{x^2}}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{-2x}{x-y}\div\dfrac{y}{x^2}
\\\\=
\dfrac{-2x}{x-y}\cdot\dfrac{x^2}{y}
\\\\=
\dfrac{-2x^3}{y(x-y)}
\\\\=
-\dfrac{2x^3}{y(x-y)}
.\end{array}
