Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 83

Answer

$1.1\times10^{7}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & \dfrac{66,000\times0.001}{0.002\times0.003} \\\\&= \dfrac{6.6\times10^{4}\times1.0\times10^{-3}}{2.0\times10^{-3}\times3.0\times10^{-3}} \\\\&= (6.6\times1.0\div2.0\div3.0)(10^{4}\times10^{-3}\div10^{-3}\div10^{-3}) \\\\&= 1.1\times10^{4+(-3)-(-3)-(-3)} \\\\&= 1.1\times10^{7} .\end{align*}
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