Answer
$16x^{6}y^{2}z^{2}$
Work Step by Step
We are given the expression $(4x^{3}yz)^{2}=(4)^{2}\times(x^{3})^{2}\times(y)^{2}\times (z)^{2}$.
To simplify further, we can use the power rule, which holds that $(a^{m})^{n}=a^{m\times n}$ (where a is a real number, and m and n are integers).
$(4)^{2}\times(x^{3})^{2}\times(y)^{2}\times (z)^{2}=16\times x^{3\times2}\times y^{2}\times z^{2}=16x^{6}y^{2}z^{2}$
