Answer
$\dfrac{x^4}{4z^2}$
Work Step by Step
Using laws of exponents, the given expression simplifies to
\begin{align*}
&
\dfrac{4^{-1}x^2yz}{x^{-2}yz^3}
\\\\&=
4^{-1}x^{2-(-2)}y^{1-1}z^{1-3}
\\&=
4^{-1}x^{4}z^{-2}
\\\\&=
\dfrac{x^4}{4z^2}
.\end{align*}