Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 37

$4^{8}y^{6}x^{2}$

$(\frac{4^{-4}}{y^{3}x})^{-2}$ [ Using $\frac{1}{a^{n}}= a^{-n}]$ $= (4^{-4}y^{-3}x^{-1})^{-2}$ $= (4^{-4})^{-2}(y^{-3})^{-2}(x^{-1})^{-2}$ [Using $(a^{m})^{n} =a^{m \times n} ]$ $=4^{8}y^{6}x^{2}$