Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 76

Answer

$3.0\times10^{-1}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & \dfrac{0.00048}{0.0016} \\\\&= \dfrac{4.8\times10^{-4}}{1.6\times10^{-3}} \\\\&= (4.8\div1.6)(10^{-4}\div10^{-3}) \\\\&= 3.0\times10^{-4-(-3)} \\\\&= 3.0\times10^{-1} .\end{align*}
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