Answer
$\dfrac{2}{y^6}$
Work Step by Step
Using laws of exponents, the given expression simplifies to
\begin{align*}
&
\dfrac{2(y^3)^{-3}}{y^{-3}}
\\\\&=
\dfrac{2y^{3(-3)}}{y^{-3}}
\\\\&=
\dfrac{2y^{-9}}{y^{-3}}
\\\\&=
2y^{-9-(-3)}
\\&=
2y^{-6}
\\\\&=
\dfrac{2}{y^6}
.\end{align*}