Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 70

Answer

$2.16\times10^{-2}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & (3.6\times10^{-12})(6\times10^{9}) \\\\&= (3.6\times6)(10^{-12}\times10^{9}) \\\\&= 21.6\times10^{-12+9} \\\\&= 21.6\times10^{-3} \\\\&= 2.16\times10^{-2} .\end{align*}
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