Answer
$\dfrac{1}{64}$
Work Step by Step
Using laws of exponents, the given expression simplifies to
\begin{align*}
&
\left( 8^{2} \right)^{-1}
\\&=
8^{2(-1)}
\\&=
8^{-2}
\\\\&=
\dfrac{1}{8^{2}}
\\\\&=
\dfrac{1}{64}
.\end{align*}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 30
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