Answer
$\dfrac{1}{-125x^{6}a^{9}}
$
Work Step by Step
Using laws of exponents, the given expression simpifies to
\begin{align*}
&
(-5y^0x^2a^3)^{-3}
\\\\&=
\dfrac{1}{(-5y^0x^2a^3)^{3}}
\\\\&=
\dfrac{1}{-5^3y^{0(3)}x^{2(3)}a^{3(3)}}
\\\\&=
\dfrac{1}{-125x^{6}a^{9}}
.\end{align*}