Answer
$\dfrac{8y^{-a+b}}{x^{3a+3b}}$
Work Step by Step
Using laws of exponents, the given expression simplifies to
\begin{align*}
&
\dfrac{16x^{-5-3a}y^{-2a-b}}{2x^{-5+3b}y^{-2b-a}}
\\\\&=
(16\div2)x^{-5-3a-(-5+3b)}y^{-2a-b-(-2b-a)}
\\\\&=
8x^{-5-3a+5-3b}y^{-2a-b+2b+a}
\\\\&=
8x^{-3a-3b}y^{-a+b}
\\\\&=
\dfrac{8y^{-a+b}}{x^{3a+3b}}
.\end{align*}