Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 21

Answer

$\dfrac{64}{27}$

Work Step by Step

\text{ Using laws of exponents, the given expression simpifies to }\\ \begin{align*} & \left( \dfrac{3}{4} \right)^{-3} \\\\&= \dfrac{3^{-3}}{4^{-3}} \\\\&= \dfrac{4^{3}}{3^{3}} \\\\&= \dfrac{64}{27} .\end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.