Answer
$\dfrac{64}{27}$
Work Step by Step
\text{
Using laws of exponents, the given expression simpifies to
}\\
\begin{align*}
&
\left( \dfrac{3}{4} \right)^{-3}
\\\\&=
\dfrac{3^{-3}}{4^{-3}}
\\\\&=
\dfrac{4^{3}}{3^{3}}
\\\\&=
\dfrac{64}{27}
.\end{align*}