Answer
$\dfrac{16}{n^{20}m^{8}}$
Work Step by Step
Using laws of exponents, the given expression simplifies to
\begin{align*}
&
\left( \dfrac{n^{5}}{2m^{-2}} \right)^{-4}
\\\\&=
\dfrac{n^{5(-4)}}{2^{-4}m^{-2(-4)}}
\\\\&=
\dfrac{n^{-20}}{2^{-4}m^{8}}
\\\\&=
\dfrac{2^4}{n^{20}m^{8}}
\\\\&=
\dfrac{16}{n^{20}m^{8}}
.\end{align*}