Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 79

Answer

$1.0\times10^{1}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & \dfrac{6000\times0.006}{0.009\times400} \\\\&= \dfrac{6.0\times10^{3}\times6.0\times10^{-3}}{9.0\times10^{-3}\times4.0\times10^2} \\\\&= (6.0\times6.0\div9.0\div4.0)(10^{3}\times10^{-3}\div10^{-3}\div10^{2}) \\\\&= 1.0\times10^{3+(-3)-(-3)-2)} \\\\&= 1.0\times10^{1} .\end{align*}
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