Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 64

Answer

$y^{26a+1}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & \dfrac{\left( y^{4a} \right)^7}{y^{2a-1}} \\\\&= \dfrac{y^{4a(7)}}{y^{2a-1}} \\\\&= \dfrac{y^{28a}}{y^{2a-1}} \\\\&= y^{28a-(2a-1)} \\\\&= y^{28a-2a+1} \\\\&= y^{26a+1} .\end{align*}
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