Answer
$D=\{x|x\geqslant 1\}= [1, \infty)$
Work Step by Step
$h(x)=\sqrt[4] {x^4-1}$,
To find the domain.
$\sqrt[4] {x^4-1}\geq0$
$ x^4\geq1$
$ x\geq1$.
Therefore the Domain is:
$D=\{x|x\geqslant 1\}= [1, \infty)$
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