Answer
$$\frac{1}{2}\sinh 2. $$
Work Step by Step
We have
$$ \int_0^1\cosh 2t dt=\frac{1}{2} \int_0^12\cosh 2t \ dt\\ = \frac{1}{2}\sinh 2t|_0^1=\frac{1}{2}(\sinh 2-\sinh 0)=\frac{1}{2}\sinh 2. $$
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