Answer
$$\frac{1}{2}\ln |x^2+1|+C$$
Work Step by Step
We integrate as follows:
\begin{align*}
\int \frac{d x}{x+x^{-1}}&=\int \frac{d x}{x+\frac{1}{x}}\\
&=\int \frac{xd x}{x^2+1}\\
&=\frac{1}{2}\ln |x^2+1|+C
\end{align*}
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