Answer
g(x) decreases when x<1, increases when x>1
Work Step by Step
$g'(x)=2x-2$
g(x) decreases when g'(x)<0, and increases when g'(x)>0
for g'(x)<0,
$2x-2<0$
$2x<2$
$x<1$
for g'(x)>0,
$2x-2>0$
$2x>2$
$x>1$
Therefore, g(x) decreases when x<1, increases when x>1
