Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 74

Answer

$\frac{7}{9}$ and $x\ne-1.$

Work Step by Step

$\frac{x+1}{3}\div\frac{3x+3}{7}=\frac{x+1}{3}\frac{7}{3(x+1)}=\frac{7}{9}$ and $x\ne-1.$
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