Answer
$\frac{y^2+2y+4}{2y}$
Work Step by Step
$\frac{y^3-8}{y^2-4}*\frac{y+2}{2y}=\frac{(y-2)(y^2+2y+4)(y+2)}{(y+2)(y-2)(2y)}=\frac{y^2+2y+4}{2y}$
NOTE: The difference of two cubes formula on the first numerator.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 61
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