Answer
$\frac{x-1}{x+2}$
Work Step by Step
$\frac{x^2-1}{x^2-4}*\frac{x^2-5x+6}{x^2-2x-3}=\frac{(x+1)(x-1)(x-2)(x-3)}{(x+2)(x-2)(x-3)(x+1)}=\frac{x-1}{x+2}$
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