Answer
$-\frac{2}{y(y+1)}$
Work Step by Step
$\frac{6y+2}{y^2-1}*\frac{1-y}{3y^2+y}=\frac{2(3y+1)(1-y)}{(y+1)(y-1)(y)(3y+1)}=-\frac{2}{y(y+1)}$
NOTE: (1-y) and (y-1) cancel out to -1 because -1 can be factored out of either to make them equal.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 60
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