Answer
$x+5$ (and $x\ne5$).
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
Hence here: $\frac{x^2-25}{x-5}=\frac{x^2-5^2}{x-5}=\frac{(x+5)(x-5)}{x-5}=x+5$ (and $x\ne5$).
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 28
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