Answer
$-\frac{2}{y(y+3)}$
Work Step by Step
$\frac{8y+2}{y^2-9}*\frac{3-y}{4y^2+y}=\frac{2(4y-1)(3-y)}{(y+3)(y-3)(y)(4y+1)}=-\frac{2}{y(y+3)}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 59
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