Answer
$\frac{3}{2}$ and $x\ne3, x\ne-7.$
Work Step by Step
$\frac{x-3}{x+7}\frac{3x+21}{2x-6}=\frac{x-3}{x+7}\frac{3(x+7)}{2(x-3)}=\frac{3}{2}$ and $x\ne3, x\ne-7.$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 51
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