Answer
$\frac{x+9}{x-1}$ and $x\ne2$.
Work Step by Step
$\frac{x^2+7x-18}{x^2-3x+2}=\frac{x^2+9x-2x-18}{x^2-x-2x+2}=\frac{x(x+9)-2(x+9)}{x(x-1)-2(x-1)}=\frac{(x+9)(x-2)}{(x-1)(x-2)}=\frac{x+9}{x-1}$ and $x\ne2$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 39
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