Answer
$\frac{x+3}{x-2}$
Work Step by Step
$\frac{x^2-9}{x^2-x-6}\times\frac{x^2+5x+6}{x^2+x-6}=\frac{(x+3)(x-3)(x+2)(x+3}{(x-3)(x+2)(x+3)(x-2)}=\frac{x+3}{x-2}$
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