Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 29

Answer

$\frac{1}{x-3}$.

Work Step by Step

$\frac{x+2}{x^2-x-6}=\frac{x+2}{x^2+2x-3x-6}=\frac{x+2}{x(x+2)-3(x+2)}=\frac{x+2}{(x+2)(x-3)}=\frac{1}{x-3}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.