Answer
$\frac{x^2+x+1}{x-2}$
Work Step by Step
$(x-3)\frac{x^2+x+1}{x^2-5x+6}=\frac{(x-3)}{1}*\frac{x^2+x+1}{(x-3)(x-2)}=\frac{x^2+x+1}{x-2}$
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