Answer
$\frac{x-2}{x-1}$
Work Step by Step
The square of a binomial difference is: $(A-B)^2=A^2-2AB+B^2$.
Hence here: $\frac{x^2-2x+1}{x^2-4x+4}\frac{(x-2)^3}{(x-1)^3}=\frac{(x-1)^2}{(x-2)^2}\frac{(x-2)^3}{(x-1)^3}=\frac{x-2}{x-1}$
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