Answer
$(x-5)(x-2i)(x+2i)$
Work Step by Step
$P(x)=x^3-5x^2+4x-20$
a) Factor the polynomial into linear and irreducible quadratic factors:
$P(x)=x^2(x-5)+4(x-5)=(x^2+4)(x-5)$.
b) Factor $P$ completely into linear factors:
$x^2+4=0\Rightarrow x=\pm 2i$
$P(x)=(x-5)(x-2i)(x+2i)$