College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 3, Polynomial and Rational Functions - Section 3.5 - Complex Zeros and the Fundamental Theorem of Algebra - 3.5 Exercises - Page 330: 37

Answer

$P(x)=x^2-2x+2$

Work Step by Step

The factor theorem says that if $f(c)=0$, then $(x-c)$ is a factor of $f(x)$ and if $(x-c)$ is a factor of $f(x)$, then $f(c)=0$. We use the given zeros $1-i$ and $1+i$ to create factors and construct the original function: $P=(x-(1+i))(x-(1-i))=x^2-2x+2$ Note that the final degree is $2$ as desired.
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