Answer
$P(x)=x^2-2x+2$
Work Step by Step
The factor theorem says that if $f(c)=0$, then $(x-c)$ is a factor of $f(x)$ and if $(x-c)$ is a factor of $f(x)$, then $f(c)=0$.
We use the given zeros $1-i$ and $1+i$ to create factors and construct the original function:
$P=(x-(1+i))(x-(1-i))=x^2-2x+2$
Note that the final degree is $2$ as desired.