Answer
Please see below.
Work Step by Step
By using the identity $e^{i \theta }= \cos \theta + i \sin \theta$, we have$$-2e^{- 2\pi i}=- 2( \cos (- 2\pi ) + i \sin (-2\pi ) )=-2.$$Now, we plot the complex number $z=-2$ the same way we plot $(-2,0)$ in the rectangular coordinate system.
