Answer
$$\int (2x+1)e^{x}dx=(2x+1)e^{x}-2e^{x}+C$$
Work Step by Step
$${[(2x+1)e^{x}]}'=(2x+1)e^{x}+2e^{x}$$
$$\int (2x+1)e^{x}dx=(2x+1)e^{x}-2\int e^{x}dx$$
$$=(2x+1)e^{x}-2e^{x}+C$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 8 - Techniques of Integration - 8.1 Integration by Parts - Exercises - Page 395: 8
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