Answer
$$\int x^{2}sin\,x\,dx=-x^{2}cos\,x+2x\,sinx+2cos\,x+C$$
Work Step by Step
$$\int x^{2}sin\,x\,dx=x^{2}(-cos\,x)-2x(-sinx)+2cos\,x-\int 0\cdot cos\,x\,dx$$
$$=-x^{2}cos\,x+2x\,sinx+2cos\,x+C$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 8 - Techniques of Integration - 8.1 Integration by Parts - Exercises - Page 395: 13
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