Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 7 - Principles Of Integral Evaluation - 7.1 An Overview Of Integration Methods - Exercises Set 7.1 - Page 490: 9

Answer

$${e^{\tan x}} + C$$

Work Step by Step

$$\eqalign{ & \int {{e^{\tan x}}{{\sec }^2}x} dx \cr & {\text{substitute }}u = \tan x,{\text{ }}du = {\sec ^2}xdx \cr & \int {{e^{\tan x}}{{\sec }^2}x} dx = \int {{e^u}du} \cr & {\text{find the antiderivative}} \cr & \int {{e^u}du} = {e^u} + C \cr & {\text{write in terms of }}x,{\text{ replace }}u = \tan x \cr & = {e^{\tan x}} + C \cr} $$
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