Answer
$j(x)=-x^2-1$.
Work Step by Step
If the vertex of a quadratic function is at $(k,m)$. Then its equation can be $f(x)=\pm(x-k)^2+m$. $+$ if it is open up, $-$ if it is open down.
Hence here the function is $j(x)=-x^2-1$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 8 - Section 8.3 - Quadratic Functions and Their Graphs - Exercise Set - Page 626: 8
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