Answer
$(2,7)$.
Work Step by Step
If the equation of a quadratic function is $f(x)=\pm(x-k)^2+m$. Then the vertex of the function is at $(k,m)$.
$-2x^2+8x-1=-2(x^2-4x)-1=-2(x-2)^2+8-1=-2(x-2)^2+7$
Hence here the vertex is $(2,7)$.
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