Answer
$(2,-11)$.
Work Step by Step
If the equation of a quadratic function is $f(x)=\pm(x-k)^2+m$. Then the vertex of the function is at $(k,m)$.
$3x^2-12x+1=3(x^2-4x)+1=3(x-2)^2-12+1=3(x-2)^2-11$
Hence here the vertex is $(2,-11)$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 8 - Section 8.3 - Quadratic Functions and Their Graphs - Exercise Set - Page 626: 14
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