Answer
$(2,-5)$.
Work Step by Step
If the equation of a quadratic function is $f(x)=\pm(x-k)^2+m$. Then the vertex of the function is at $(k,m)$.
$2x^2-8x+3=2(x^2-4x)+3=2(x-2)^2-8+3=2(x-2)^2-5$
Hence here the vertex is $(2,-5)$.
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