Answer
$ f(x)=2(x+10)^2-5$.
Work Step by Step
Given equation of the parabola is $f(x)=2x^2$.
vertex $(h,k)=(-10,-5)$.
The equation of the parabola that has the same shape is
$\Rightarrow f(x)=2(x-h)^2+k$
Substitute the values of $h$ and $k$.
$\Rightarrow f(x)=2(x-(-10))^2+(-5)$
Simplify.
$\Rightarrow f(x)=2(x+10)^2-5$.
