Answer
$$\sinh ^{-1}(1)$$
Work Step by Step
\begin{aligned} \int_{0}^{1} \frac{1}{\sqrt{1+x^{2}}} d x &=\left.\sinh ^{-1} x\right|_{0} ^{1} \\ &=\sinh ^{-1}(1)-\sinh ^{-1}(0) \\ &=\sinh ^{-1}(1)-0 \\ &=\sinh ^{-1}(1) \end{aligned}
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