Answer
$$\cosh ^{-1} x+C $$
Work Step by Step
Since $$\frac{d}{d x} \cosh ^{-1} x=\frac{1}{\sqrt{x^{2}-1}} $$
Then $$ \int \frac{1}{\sqrt{x^{2}-1}} d x=\cosh ^{-1} x+C $$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 8 - Techniques of Integration - 8.4 Integrals Involving Hyperbolic and Inverse Hyperbolic Functions - Exercises - Page 415: 17
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