Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.4 Integrals Involving Hyperbolic and Inverse Hyperbolic Functions - Exercises - Page 415: 10

Answer

$$-\frac{1}{2} \operatorname{csch}\left(x^{2}\right)+C$$

Work Step by Step

Given $$\int x \operatorname{csch}\left(x^{2}\right) \operatorname{coth}\left(x^{2}\right) d x $$ Let $$ u= x^2 \ \ \ \to du = 2x dx$$ Then \begin{aligned} \int x \operatorname{csch}\left(x^{2}\right) \operatorname{coth}\left(x^{2}\right) d x &=-\frac{1}{2} \int d u \\ &=-\frac{1}{2} u+C \\ &=-\frac{1}{2} \operatorname{csch}\left(x^{2}\right)+C\end{aligned}
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