Answer
$G'(x)=-\dfrac{C(\ln4)4^{C/x}}{x^{2}}$
Work Step by Step
$G(x)=4^{C/x}$ (Here, $C$ is a constant)
Differentiate using the chain rule:
$G'(x)=4^{C/x}(\ln4)(\dfrac{C}{x})'=...$
Rewrite $\dfrac{C}{x}$ as $Cx^{-1}$ and continue with the differentiation process:
$...=4^{C/x}(\ln4)(\dfrac{C}{x})'=4^{C/x}(\ln4)(Cx^{-1})'=4^{C/x}(\ln4)(-Cx^{-2})$
$G'(x)=-\dfrac{C(\ln4)4^{C/x}}{x^{2}}$
