Answer
$f'(t)=3(\ln2)t^{2}(2^{t^{3}})$
Work Step by Step
$f(t)=2^{t^{3}}$
Differentiate using the chain rule:
$f'(t)=(2^{t^{3}})(\ln2)(t^{3})'=(2^{t^{3}})(\ln2)(3t^{2})=3(\ln2)t^{2}(2^{t^{3}})$
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